Let RR be a Euclidean domain with valuation vv such that v(ab)v(b)v(ab) \geq v(b) for all non-zero a,bR.a,b \in R.

Proposition A

Any two associate elements a,bRa,b \in R have the same valuation.

Proof

Let a,bRa, b \in R be non-zero associate elements, and let au=bau = b and bu=a.bu' = a. In that case, v(au)=v(b)v(a)v(au) = v(b) \geq v(a) and v(bu)=v(a)v(b).v(bu') = v(a) \geq v(b). Hence v(a)=v(b).v(a) = v(b).

\blacksquare

Proposition B

The units of BB have minimum valuation.

Proof

Since (by Proposition A) all units have the same valuation, it is enough to prove that 11 has minimum valuation. Observe that, for all non-zero aR,a \in R, v(a)=v(a1)v(1).v(a) = v(a \cdot 1) \geq v(1).

\blacksquare