Proposition

Every countable set can be well-ordered.

Proof

Standard order relation on N\mathbb{N} is a well-order. A countable set SS is isomorphic to N\mathbb{N} and if f:SNf : S \to \mathbb{N} is a bijection, then we can define a well-ordering on SS by ab    f(a)f(b).a \leq b \iff f(a) \leq f(b).

In the concrete case of S=Z,S = \mathbb{Z}, we can define f(0)=0,f(0) = 0, f(n)=2n1f(-n) = 2n - 1 and f(n)=2nf(n) = 2n for n>0.n > 0. This is clearly a bijection.

\blacksquare